In an ap s5+s7 167

WebOct 15, 2024 · S5+S7=167 therefore 2a+10d=167 and a+9d=235 from these 2 equations we get d=12.625 therefore the ap starts with 40.75 and continue s with a difference d=12.625 olf they have given sum of terms not nth term, so the formula you're using is wrong...……... Find Math textbook solutions? See all Class Class 12 Class Class 11 Class Class 10 Class … WebThe sum of the sum of first five terms of an AP and the sum of the first seven terms of the same AP is 167. ... Consider an A.P. whose first term and the common difference are a and d respectively. According to the question: S5 + S7 = 167 (Given) \Rightarrow \frac{5}{2}[2 a+(5-1) d]+\frac{7}{2}[2 a+(7-1) d]=167\\ \Rightarrow 5\{2 a+4 d\}+7\{2 ...

In an AP if S5 + S7 = 167 and S10 = 235. Then find the AP, …

WebJul 9, 2024 · closed Jul 10, 2024 by Anaswara In an AP. It is given that S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. arithmetic progression class-10 1 Answer +2 votes answered Jul 9, 2024 by Dheeya (31.0k points) selected Jul 10, 2024 by Anaswara Best answer WebNov 6, 2024 · In an AP,it is given that S5+S7 =167 and S10=235 then find the AP,where Sn denotes the sum of its first n terms. See answers Advertisement BigSmoke Here your … inch sanitary fitting gasket https://dovetechsolutions.com

in an AP ; if S5+S7 =167 and S10 = 235 then find the AP ; where Sn ...

WebJun 24, 2024 · It is given that S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. asked Jul 9, 2024 in Arithmetic Progression by Anaswara (31.5k points) arithmetic progression; class-10; ... In an A.P. if S5 + S7 = 167 and S10 = 235, then find the A.P., where Sn, denotes the sum of first n terms. asked Sep 29, ... WebJan 24, 2024 · Step-by-step explanation: Answer We know that sum of n terms sn = n/2 (2a + (n - 1) * d) Given s5 + s7 = 167. = 5/2 (2a + (5 - 1) * d) + 7/2 (2a + (7 - 1) d) = 167 = 5/2 (2a + 4d) + 7/2 (2a + 6d) = 167 = 5 (a + 2d) + 7 (a + 3d) = 167 = 5a + 10d + 7a + 21d = 167 = 12a + 31d = 167 ---------- (1) Given that s10 = 235 10/2 (2a + (10 - 1) * d) = 235 WebIn an A.P., S5 + S7 = 167 and S10 = 235, then find the A.P., where Sn denotes the sum of first n terms. Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic … income tax old vs new regime comparison

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In an ap s5+s7 167

In an AP if S5 + S7 = 167 and S10 = 235. Then find the AP, …

WebIn an AP, if S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. Solution: Question 25. The fourth term of an A.P. is 11. The sum of the fifth and seventh terms of the A.P. is 34. Find its common difference Solution: Question 26. WebIn an AP. It is given that S 5 + S 7 = 167 and S 10 = 235 , then find the AP, where S n denotes the sum of its first n terms. arithmetic progression class-10 1 Answer +1 vote answered …

In an ap s5+s7 167

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WebNov 30, 2024 · In an AP, if S5 +S7 =167 and S10 =235, then find the AP, where Sn denotes the sum of its first n terms. [2015] ...[2M] Corporate Off. The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebJan 2, 2024 · thesarcasticsoul Answer: S5+S7=5/2(2a+4d) +7/2(2a+6d)=167 =5a+10d+7a+21d=167 =12a+31d=167 [let this be eqn 1] similarly, from S10=235, we get 2a+9d=47 {let this be equation 2} by solving eqn 1 and 2, we get a=1 and d=5 therefore the ap is 1,6,11........ Step-by-step explanation: Advertisement Advertisement New questions in …

WebLet a and d be the first term and the common difference of the AP, respectively Chapter Chosen. Arithmetic Progressions Book Chosen. Mathematics Subject Chosen. Mathematics ... In an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, Where S n denotes the sum of its first n terms. Let a and d be the first term and the common difference of ... WebApr 12, 2024 · In an AP, If S5 + S7 = 167 and S10 = 235 then find the AP, where Sn - YouTube In this video i solved important questions of class 10 maths for term 2,the question is as followingIn an AP,...

WebIn an AP, S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms urgently need this answer!!!! - Maths - Arithmetic Progressions WebIt is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. Arithmetic Progression CBSE Class 10 Maths RS Aggarwal. In an AP. …

WebIn an AP, if S 5 + S 7 = 167 and S 10 = 235, then find the AP, where S n denotes the sum of its first n terms.

WebIn an A.P., if S5 + S7 = 167 and S 10= 235, then find the A.P., where Sn denotes the sum of its first n terms. Advertisement Remove all ads Solution S S and S S 5 + S 7 = 167 and S 10 = … inch sayingsWebIn an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms Arithmetic Progression CBSE Class 10 Maths RS Aggarwal In an AP. income tax old vs new slabWebIn an AP if S5+S7 =167 and S10 =235 then find S6. Class 10 cbse AP extra questions RR Maths Mantra 5 subscribers Subscribe 37 views 10 months ago #cbseclass10 … inch schoolhouse downpatrickWebJan 19, 2024 · 14K views 3 years ago Arithmetic Progressions In an AP, if S5 + S7 = 167 and S10 = 235, then find the AP, where Sn denotes the sum of its first n terms. Show more The … inch schoolhouseWebFeb 1, 2024 · In an AP. It is given that S5 + S7 = 167 and S10 = 235 , then find the AP, where Sn denotes the sum of its first n terms. asked Sep 14, 2024 in Mathematics by Mubarak (32.9k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to ... inch san pedroWebMay 29, 2024 · in an AP ;if S5+S7=167 and S10=235 then find the AP ; where Sn denote the sum of its first n terms ANSWER: let a and b be the first term common difference of the AP,respectively therefore ,sum of n terms ,Sn =n/2 (2a+ (n-1)d) we have S5+S7=167 ⇒ 5/2 (2a+4d)+7/2 (2a+6d)=167 ⇒ 5 (a+2d)+7 (a+3d)=167 ⇒ 12a+31d=167 ----- (1) also, S10=235 income tax on 1040 form 2020income tax on 10 000