WebMar 28, 2024 · p O H = − log [ 10 − 7] = − ( − 7) = 7. Thus, both the pH = 7 and pOH = 7 for pure water. This makes sense, since the pH and pOH should sum to 14, as shown in … WebGUIA DE QUIMICA 11. Calcule la H+ Y LA OH- de las siguientes disoluciones Disolución de pH 6,2 [H+]= antilog-6,2 = 6,3x10-7 [OH-]= 1x10-14 / 6,3x10-7 = 1,5x10-8 [H+ ...
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WebAt 25ºC, Kw = [OH-] [H+] = 1x10-14 [OH-] = 1x10-14/ .2 = 5x10-14 b. 5 x 10-10 M [OH-] = 1x10-14/ 5 x 10-10 = 2 x 10-5 c. 100 M [OH-] = 1x10-14/ 100 = 1x10-16 3. For each of these strong acid/base solutions, calculate the molarity of OH-, H+, pH and pOH a. 0.01M NaOH [OH-] = 0.01 pOH = 2 [H+] = 1x10-14/.01 = 1x10-12 pH = 12 b. 5M HNO3 [H+] = 5 ... Web[OH-]=1x10^-7 M [OH-]=1x10^5 M None [OH-]=1x10-8 M [OH-]=1x10^6 M Calculate the pOH of [H+]=2.5x10^-5 M. None 14.0 4.0 x 10^-10 4.60 9.40 Which of the following will have the most acidic (lowest pH)? [OH-]=1x10^-7 M [OH-]=1x10^5 M None [OH-]=1x10-8 M [OH-]=1x10^6 M Calculate the pOH of [H+]=2.5x10^-5 M. None 14.0 4.0 x 10^-10 4.60 9.40 … north carolina freedom caucus
Calculate the pH of a 0.25 M NaOH solution. Note: Kw = [OH-] x …
WebPerform some calculations to complete the following table: [OH+] [H3O+] pH [H3O+]= 1X10^-5, find [OH+} and pH [OH-]= 1X10^-3, find [H3O+] and pH [H3O+]=1X10^-8, find [OH-], pH … WebK w is an ionic product of water and its value is 1x10-14 at 25°C. [H +] [OH-] = 1x10-14 Pure water dissociate completely and has equal concentration. Thus [H +] = [OH-] [H +] [H +] = … WebMay 16, 2024 · From pH = 8.60, we can find [H +] and hence [OH - ]. [H +] = 1x10 -8.60 = 2.51x10 -9 M [OH -] = 1x10 -14 /2.51x10 -9 = 3.98x10 -6 M (This can also be found from pOH: pOH = 14-pH = 14-8.60 = 5.4 and OH = 10 -5.4 = 3.98x10 -6 M) Kb = (3.98x10 -6 ) (3.98x10 -6 )/0.016 - 3.98x10 -6 and assuming 3.98x10-6 is small relative to 0.016, ignore it... north carolina free money search